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when 290 liters/sec of water flow in a 30 cm pipeline,82 hp are lost in 300 meter pipe.calculate head lost?
calculate head lost and friction factor and wall shear stress
we consider p as a dropping pressure, Q as a fluid flow, and P as a lost(capital P). then we have the following equation:
P=pQ (1)
first we change all the units to the SI units:
P=82hp=82x745.7Watt=61147.4Watt (2)
Q=290lit/s=.29m^3/s (3)
then from (1),(2), and (3) we have:
61147(Watt)=px.29(m^3/s) (4)
then
p=61147(Watt)/.29(m^3/s) =210853Pascal (5)
also we have the following pressure head formula:
p=Roxgxh (6)
where Ro is density, g is the gravity acceleration, and h is pressure head. then from (6) we have
210853(Pa)=1000(kg/m^3)x10xh (7)
and finally the pressure head lost(h) will be:
h=21.08 m (8)
I hope it can be useful for you.
Regards
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